561

Deutz-Fahr 561 – ECU: Missing Injector Correction Value for Injector 3

Issue description

The Engine Control Unit (ECU) has detected that the Injector Matching Amount (IMA) code for the third injector is missing or out of calibration. This unique alphanumeric code compensates for manufacturing variations to ensure precise fuel delivery. Without it, the ECU reverts to a default setting, which can negatively affect the proper operation of the engine's fuel injection system and lead to performance issues.

Applies to these machines

  • Deutz TD 2.9 L4
  • Engines with EMR3
  • Engines with EMR4
  • Engines with EDC17CV5x

Check the cause

  1. Verify if injector 3 was recently replaced without programming the new injector's IMA code into the ECU (most common cause)

  2. Scan for other fault codes to determine if the issue is isolated to calibration data or if there are underlying wiring or injector hardware problems

  3. Physically inspect injector 3 to locate and record the printed IMA code on its body

Repair steps

  1. Connect diagnostic tool

    Connect a compatible diagnostic scanner (such as Deutz SerDia or a generic J1939 tool) to the vehicle's diagnostic port.

  2. Navigate to injector coding

    Within the diagnostic software, access the service or calibration menu and find the function for injector coding or injector calibration.

  3. Select cylinder 3

    Choose cylinder number 3 to program its corresponding injector.

  4. Enter the IMA code

    Carefully input the alphanumeric IMA code that is printed on the body of the injector for cylinder 3. It is crucial that this code is entered exactly as it appears.

  5. Program and verify

    Save the new code to the ECU. Confirm that the programming was successful, clear all fault codes, and run the engine to ensure fault code 561 does not reappear.

  6. Perform ECU adaptation

    Drive the vehicle at a constant speed for a period to allow the ECU to go through its learning process and fine-tune engine performance with the new data.

Parts you might need

(7)

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